Searched refs:FooType (Results 1 – 7 of 7) sorted by relevance
| /external/clang/test/Index/ |
| D | print-type.c | 1 typedef int FooType; typedef
3 int *f(int *p, char *x, FooType z, int arr[5], void (*fn)(int)) { in f()
5 const FooType w = z; in f()
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| D | print-type.cpp | 19 typedef int FooType; typedef
21 int *f(int *p, char *x, FooType z) { in f()
22 const FooType w = z; in f()
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| /external/clang/test/Analysis/ |
| D | variadic-method-types.m | 69 typedef struct FooType * __attribute__ ((NSObject)) FooType;
73 void f(id a, id<P> b, C* c, C<P> *d, FooType fooType, BarType barType) {
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| D | security-syntax-checks.m | 36 typedef float FooType;
37 …for (FooType x = 100000001.0f; x <= 100000010.0f; x++ ) {} // expected-warning{{Variable 'x' with …
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| /external/libcxx/test/std/utilities/function.objects/func.invoke/ |
| D | invoke.pass.cpp | 283 using FooType = int&(NonCopyable&&); in bullet_five_tests() typedef
285 FooType& fn = foo; in bullet_five_tests()
289 FooType* fn = foo; in bullet_five_tests()
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| /external/swiftshader/third_party/llvm-7.0/llvm/test/Bindings/llvm-c/ |
| D | debug_info.ll | 24 ; CHECK-NEXT: !FooType = !{!16}
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| /external/googletest/googletest/docs/ |
| D | faq.md | 680 If you use a user-defined type `FooType` in an assertion, you must make sure
681 there is an `std::ostream& operator<<(std::ostream&, const FooType&)` function
682 defined such that we can print a value of `FooType`.
684 In addition, if `FooType` is declared in a name space, the `<<` operator also
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