Searched refs:bessel_i1 (Results 1 – 5 of 5) sorted by relevance
6 `bessel_i1e(x) = exp(-abs(x)) bessel_i1(x)`.8 This function is faster and numerically stabler than `bessel_i1(x)`.
197 self.evaluate(special_math_ops.bessel_i1(x_single)))199 self.evaluate(special_math_ops.bessel_i1(x_double)))
111 def bessel_i1(x, name=None): function
68 name: "bessel_i1"