Searched refs:splitPerm (Results 1 – 5 of 5) sorted by relevance
148 val splitPerm = spi.splitPermission in <lambda>() constant151 app.packageManager.getPermissionInfo(splitPerm, 0) in <lambda>()153 Log.w(LOG_TAG, "No such permission: $splitPerm", e) in <lambda>()
422 SplitPermissionInfo splitPerm = splitPerms.get(i); in parseFromXml() local423 if (backupPlatformVersion < splitPerm.getTargetSdk() in parseFromXml()424 && permName.equals(splitPerm.getSplitPermission())) { in parseFromXml()425 expandedPermissions.addAll(splitPerm.getNewPermissions()); in parseFromXml()
153 PermissionManager.SplitPermissionInfo splitPerm = splitPerms.get(splitPermNum); in addSplitPermissions() local155 if (targetSDK < splitPerm.getTargetSdk() in addSplitPermissions()156 && splitPerm.getSplitPermission().equals(reqPerm)) { in addSplitPermissions()157 expandedPerms.addAll(splitPerm.getNewPermissions()); in addSplitPermissions()
1221 PermissionManager.SplitPermissionInfo splitPerm = splitPerms.get(i);1223 if (requestingAppTargetSDK < splitPerm.getTargetSdk()1224 && permission.equals(splitPerm.getSplitPermission())) {1225 extendedBySplitPerms.addAll(splitPerm.getNewPermissions());
1502 String splitPerm = spi.getSplitPermission();1506 pi = mPackageManager.getPermissionInfo(splitPerm, 0);1508 Log.w(LOG_TAG, "No such permission: " + splitPerm, e);