Searched refs:n32 (Results 1 – 1 of 1) sorted by relevance
1260 long n32 = 32L * n; // block length in bits in divideAndRemainderBurnikelZiegler() local1261 … int sigma = (int) Math.max(0, n32 - b.bitLength()); // step 3: sigma = max{T | (2^T)*B < beta^n} in divideAndRemainderBurnikelZiegler()1268 int t = (int) ((aShifted.bitLength()+n32) / n32); in divideAndRemainderBurnikelZiegler()