Searched refs:word_len (Results 1 – 1 of 1) sorted by relevance
666 let word_len: u32 = word.len().try_into().unwrap(); in hyphenate_with_no_pattern() localVariable668 for i in 1..word_len { in hyphenate_with_no_pattern()696 && i <= word_len - self.min_suffix in hyphenate_with_no_pattern()