Searched refs:naive (Results 1 – 1 of 1) sorted by relevance
55 double naive = 0; in testCompensatedSums() local81 naive += square(DoubleStream.of(rand).reduce((x, y) -> x+y).getAsDouble() - sum[0]); in testCompensatedSums()106 Assert.assertTrue(naive > jdkSequentialStreamError); in testCompensatedSums()107 Assert.assertTrue(naive > jdkParallelStreamError); in testCompensatedSums()