Searched refs:packageToPermInfoEntry (Results 1 – 2 of 2) sorted by relevance
144 packageToPermInfoEntry: Map.Entry<Pair<String, UserHandle>, AppPermGroupUiInfo> -> in <lambda>() method145 val appPermGroupUiInfo = packageToPermInfoEntry.value in <lambda>()
519 packageToPermInfoEntry: Map.Entry<Pair<String, UserHandle>, AppPermGroupUiInfo> -> in <lambda>() method520 val appPermGroupUiInfo = packageToPermInfoEntry.value in <lambda>()