Searched refs:LONG_POWERS_OF_TEN_BIT_LENGTH (Results 1 – 1 of 1) sorted by relevance
158 …private static final int[] LONG_POWERS_OF_TEN_BIT_LENGTH = new int[MathUtils.LONG_POWERS_OF_TEN.le… field in BigDecimal187 for (int i = 0; i < LONG_POWERS_OF_TEN_BIT_LENGTH.length; ++i) {188 LONG_POWERS_OF_TEN_BIT_LENGTH[i] = bitLength(MathUtils.LONG_POWERS_OF_TEN[i]);764 … Math.max(thisValue.bitLength,augend.bitLength+LONG_POWERS_OF_TEN_BIT_LENGTH[diffScale])+1<64) { in addAndMult10()861 … Math.max(this.bitLength,subtrahend.bitLength+LONG_POWERS_OF_TEN_BIT_LENGTH[diffScale])+1<64) { in subtract()869 … Math.max(this.bitLength+LONG_POWERS_OF_TEN_BIT_LENGTH[diffScale],subtrahend.bitLength)+1<64) { in subtract()1044 divisor.bitLength + LONG_POWERS_OF_TEN_BIT_LENGTH[(int)diffScale] < 64) { in divide()1052 this.bitLength + LONG_POWERS_OF_TEN_BIT_LENGTH[(int)-diffScale] < 64) { in divide()1881 (this.bitLength + LONG_POWERS_OF_TEN_BIT_LENGTH[(int)diffScale]) < 64 ) { in setScale()1971 bitLength + LONG_POWERS_OF_TEN_BIT_LENGTH[(int)-newScale] < 64 ) { in movePoint()