1 /*
2  * Copyright (C) 2013 The Android Open Source Project
3  * All rights reserved.
4  *
5  * Redistribution and use in source and binary forms, with or without
6  * modification, are permitted provided that the following conditions
7  * are met:
8  *  * Redistributions of source code must retain the above copyright
9  *    notice, this list of conditions and the following disclaimer.
10  *  * Redistributions in binary form must reproduce the above copyright
11  *    notice, this list of conditions and the following disclaimer in
12  *    the documentation and/or other materials provided with the
13  *    distribution.
14  *
15  * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
16  * "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
17  * LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS
18  * FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE
19  * COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT,
20  * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING,
21  * BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS
22  * OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED
23  * AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY,
24  * OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT
25  * OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
26  * SUCH DAMAGE.
27  */
28 
29 // Contains an implementation of all stdlib functions missing from bionic.
30 //
31 // TODO(digit): Make these work.
32 
33 #include <inttypes.h>
34 #include <stdlib.h>
35 #include <assert.h>
36 
strtold(const char * nptr,char ** endptr)37 long double strtold(const char* nptr, char** endptr) {
38   //FIXME: Although in Android long double is the same as double, can we borrow stdtod?
39   return strtod(nptr, endptr);
40 }
41 
imaxabs(intmax_t j)42 intmax_t imaxabs(intmax_t j)
43 {
44   return (j < 0 ? -j : j);
45 }
46 
imaxdiv(intmax_t numer,intmax_t denom)47 imaxdiv_t imaxdiv(intmax_t numer, intmax_t denom)
48 {
49   imaxdiv_t retval;
50 
51   retval.quot = numer / denom;
52   retval.rem = numer % denom;
53   if (numer >= 0 && retval.rem < 0) {
54     retval.quot++;
55     retval.rem -= denom;
56   }
57   return (retval);
58 }
59