Searched refs:subprops (Results 1 – 1 of 1) sorted by relevance
545 XmlProperty[] subprops = new XmlProperty[j - i]; in sortNatural() local547 subprops[index] = properties.get(k); in sortNatural()549 Arrays.sort(subprops, Property.PRIORITY); in sortNatural()562 for (int k = 0, n = subprops.length; k < n; k++) { in sortNatural()563 String nextName = subprops[k].getName(); in sortNatural()585 subprops); in sortNatural()586 complexProperty.setPriority(subprops[0].getPriority()); in sortNatural()591 for (XmlProperty p : subprops) { in sortNatural()