Lines Matching refs:bit

35  The precision of the mathematical operations on 32 bit floats is affected by the pragmas
46  <li>half_: May perform internal computations using 16 bit floats.  Additionally, subnormal
54 summary: 1 / pi, as a 32 bit float
56  The inverse of pi, as a 32 bit float.
61 summary: 2 / pi, as a 32 bit float
63  2 divided by pi, as a 32 bit float.
70 summary: 2 / pi, as a 32 bit float
72  2 divided by pi, as a 32 bit float.
77 summary:  2 / sqrt(pi), as a 32 bit float
79  2 divided by the square root of pi, as a 32 bit float.
84 summary: e, as a 32 bit float
86  The number e, the base of the natural logarithm, as a 32 bit float.
91 summary: log_e(10), as a 32 bit float
93  The natural logarithm of 10, as a 32 bit float.
98 summary: log_e(2), as a 32 bit float
100  The natural logarithm of 2, as a 32 bit float.
105 summary: log_10(e), as a 32 bit float
107  The logarithm base 10 of e, as a 32 bit float.
112 summary: log_2(e), as a 32 bit float
114  The logarithm base 2 of e, as a 32 bit float.
119 summary: pi, as a 32 bit float
121  The constant pi, as a 32 bit float.
126 summary: pi / 2, as a 32 bit float
128  Pi divided by 2, as a 32 bit float.
133 summary: pi / 4, as a 32 bit float
135  Pi divided by 4, as a 32 bit float.
140 summary: 1 / sqrt(2), as a 32 bit float
142  The inverse of the square root of 2, as a 32 bit float.
147 summary: sqrt(2), as a 32 bit float
149  The square root of 2, as a 32 bit float.
1125 summary: Reciprocal computed to 16 bit precision
1129  The precision is that of a 16 bit floating point value.
1141 summary: Reciprocal of a square root computed to 16 bit precision
1145  The precision is that of a 16 bit floating point value.
1157 summary: Square root computed to 16 bit precision
1161  The precision is that of a 16 bit floating point value.
2222  expected from using 16 bit floating point values.
2249  expected from using 16 bit floating point values.
2276  expected from using 16 bit floating point values.