Lines Matching refs:room

442 whether there is room for the new growth in the current chunk.  If you
454 The function @code{obstack_room} returns the amount of room available
465 While you know there is room, you can use these fast growth functions
499 enough room for what you want to add, the fast growth functions
502 new chunk; then there will be lots of room available again.
518       int room = obstack_room (obstack);
519       if (room == 0)
521           /* @r{Not enough room. Add one character slowly,}
522              @r{which may copy to a new chunk and make room.}  */
528           if (room > len)
529             room = len;
530           /* @r{Add fast as much as we have room for.} */
531           len -= room;
532           while (room-- > 0)
736 that there is enough room.  @xref{Extra Fast Growing}.
740 checking that there is enough room.  @xref{Extra Fast Growing}.
743 Get the amount of room now available for growing the current object.