Searched refs:adj0 (Results 1 – 1 of 1) sorted by relevance
351 double adj0, tol; local950 adj0 = dval(&adj) = 1.;953 adj0 = dval(&adj) *= 0.5;959 L = adj0;960 adj0 -= L;963 if (adj0 >= .5)967 if (asub && adj0 > 0.)971 if (!asub && adj0 > 0.) {1058 dval(&adj) = adj0 - .5;1060 if (adj0 > tol) {[all …]