Searched refs:ab0x (Results 1 – 1 of 1) sorted by relevance
115 double ab0x = a[0].fX - b[0].fX; in intersect() local116 double numerA = ab0y * bxLen - byLen * ab0x; in intersect()117 double numerB = ab0y * axLen - ayLen * ab0x; in intersect()