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Searched refs:nnzL (Results 1 – 4 of 4) sorted by relevance

/external/eigen/Eigen/src/SparseLU/
DSparseLU_Utils.h21 void SparseLUImpl<Scalar,Index>::countnz(const Index n, Index& nnzL, Index& nnzU, GlobalLU_t& glu) in countnz() argument
23 nnzL = 0; in countnz()
37 nnzL += jlen; in countnz()
DSparseLUImpl.h54 void countnz(const Index n, Index& nnzL, Index& nnzU, GlobalLU_t& glu);
/external/eigen/Eigen/src/IterativeLinearSolvers/
DIncompleteLUT.h272 Index nnzL = fill_in/2; in factorize() local
273 Index nnzU = nnzL; in factorize()
274 m_lu.reserve(n * (nnzL + nnzU + 1)); in factorize()
403 len = (std::min)(sizel, nnzL); in factorize()
/external/eigen/bench/spbench/
Dtest_sparseLU.cpp90 cout << "Number of nonzeros in the factor : " << solver.nnzL() + solver.nnzU() << std::endl; in main()