Searched refs:out_nbrs (Results 1 – 7 of 7) sorted by relevance
316 def out_nbrs(self, node): member in Graph334 l = dict.fromkeys( self.inc_nbrs(node) + self.out_nbrs(node) )457 get_nbrs = self.out_nbrs633 nbr_set = set(self.out_nbrs(node))639 sec_set = set(self.out_nbrs(nbr))
34 for w in graph.out_nbrs(v):
87 for nbr in graph.out_nbrs(node):
143 return graph.out_nbrs(node)
40 for tail in g.out_nbrs(head):48 edgefn=lambda node: list(sorted(g.out_nbrs(node)))[:-1],71 for tail in list(sorted(g.out_nbrs(head)))[:-1]:
126 self.assertEqual(list(sorted(graph.out_nbrs(1))), [2, 3, 5])
198 .. method:: Graph.out_nbrs(node)