Searched refs:i0 (Results 1 – 3 of 3) sorted by relevance
34 for (int i0 = 7 - 1; i0 >= 1; i0--) { in doit()35 …mA[6][0][0] -= ((((l0++) == ( -mX)) ? (((mA[3][i0][1] > 503) || (mX <= i0)) ? (--l0) : (l0--)) : m… in doit()38 for (int i1 = i0-2 - 1; i1 >= 3; i1--) { in doit()39 for (int i2 = 2; i2 < i0; i2++) { in doit()40 mA[i0][4][l3] >>= 1; in doit()49 for (int i0 = 0; i0 < 10; i0++) in main()52 mA[i0][i1][i2] = k++; in main()
137 # i0 = phi(p0,i1) \141 # i1 = phi(p0, i0)
1336 int i0 = 0; in largeFrame() local3336 i1 += i0; in largeFrame()