Searched refs:a20 (Results 1 – 2 of 2) sorted by relevance
715 double a20 = m[6]; in invert() local722 double t10 = a20 * a12 - a10 * a22; in invert()723 double t11 = a00 * a22 - a20 * a02; in invert()725 double t20 = a10 * a21 - a20 * a11; in invert()726 double t21 = a20 * a01 - a00 * a21; in invert()
475 Target.Floaty a20 = t.multiply(t.newFloaty(v1[2]), t.newFloaty(v2[0])); in cross() local476 out[1] = t.subtract(a20, a02); in cross()491 Target.Floaty a20 = t.multiply(t.new32(v1[2]), t.new32(v2[0])); in cross() local492 out[1] = t.subtract(a20, a02); in cross()