Searched refs:createIndexName (Results 1 – 1 of 1) sorted by relevance
109 name = createIndexName(listOf(it.columnName), tableName), in <lambda>()465 name = createIndexName(it.columnNames, tableName), in <lambda>()518 createIndexName(fieldInput, tableName) in <lambda>()526 private fun createIndexName(columnNames: List<String>, tableName: String): String { in <lambda>() method