1; This testcase comes from this C fragment: 2; 3; void test(unsigned Num, int *Array) { 4; unsigned i, j, k; 5; 6; for (i = 0; i != Num; ++i) 7; for (j = 0; j != Num; ++j) 8; for (k = 0; k != Num; ++k) 9; printf("%d\n", i+k+j); /* Reassociate to (i+j)+k */ 10;} 11; 12; In this case, we want to reassociate the specified expr so that i+j can be 13; hoisted out of the inner most loop. 14; 15; RUN: opt < %s -reassociate -S | FileCheck %s 16; END. 17@.LC0 = internal global [4 x i8] c"%d\0A\00" ; <[4 x i8]*> [#uses=1] 18 19declare i32 @printf(i8*, ...) 20 21; Check that (i+j) has been reassociated (i=reg115, j=reg116) 22; CHECK: %reg113 = add i32 %reg116, %reg115 23define void @test(i32 %Num, i32* %Array) { 24bb0: 25 %cond221 = icmp eq i32 0, %Num ; <i1> [#uses=3] 26 br i1 %cond221, label %bb7, label %bb2 27bb2: ; preds = %bb6, %bb0 28 %reg115 = phi i32 [ %reg120, %bb6 ], [ 0, %bb0 ] ; <i32> [#uses=2] 29 br i1 %cond221, label %bb6, label %bb3 30bb3: ; preds = %bb5, %bb2 31 %reg116 = phi i32 [ %reg119, %bb5 ], [ 0, %bb2 ] ; <i32> [#uses=2] 32 br i1 %cond221, label %bb5, label %bb4 33bb4: ; preds = %bb4, %bb3 34 %reg117 = phi i32 [ %reg118, %bb4 ], [ 0, %bb3 ] ; <i32> [#uses=2] 35 %reg113 = add i32 %reg115, %reg117 ; <i32> [#uses=1] 36 %reg114 = add i32 %reg113, %reg116 ; <i32> [#uses=1] 37 %cast227 = getelementptr [4 x i8], [4 x i8]* @.LC0, i64 0, i64 0 ; <i8*> [#uses=1] 38 call i32 (i8*, ...) @printf( i8* %cast227, i32 %reg114 ) ; <i32>:0 [#uses=0] 39 %reg118 = add i32 %reg117, 1 ; <i32> [#uses=2] 40 %cond224 = icmp ne i32 %reg118, %Num ; <i1> [#uses=1] 41 br i1 %cond224, label %bb4, label %bb5 42bb5: ; preds = %bb4, %bb3 43 %reg119 = add i32 %reg116, 1 ; <i32> [#uses=2] 44 %cond225 = icmp ne i32 %reg119, %Num ; <i1> [#uses=1] 45 br i1 %cond225, label %bb3, label %bb6 46bb6: ; preds = %bb5, %bb2 47 %reg120 = add i32 %reg115, 1 ; <i32> [#uses=2] 48 %cond226 = icmp ne i32 %reg120, %Num ; <i1> [#uses=1] 49 br i1 %cond226, label %bb2, label %bb7 50bb7: ; preds = %bb6, %bb0 51 ret void 52} 53