1 %{
2 /* Expression parsing for plural form selection.
3    Copyright (C) 2000, 2001 Free Software Foundation, Inc.
4    Written by Ulrich Drepper <drepper@cygnus.com>, 2000.
5 
6    This program is free software; you can redistribute it and/or modify it
7    under the terms of the GNU Library General Public License as published
8    by the Free Software Foundation; either version 2, or (at your option)
9    any later version.
10 
11    This program is distributed in the hope that it will be useful,
12    but WITHOUT ANY WARRANTY; without even the implied warranty of
13    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
14    Library General Public License for more details.
15 
16    You should have received a copy of the GNU Library General Public
17    License along with this program; if not, write to the Free Software
18    Foundation, Inc., 51 Franklin Street - Fifth Floor, Boston, MA 02110-1301,
19    USA.  */
20 
21 /* The bison generated parser uses alloca.  AIX 3 forces us to put this
22    declaration at the beginning of the file.  The declaration in bison's
23    skeleton file comes too late.  This must come before <config.h>
24    because <config.h> may include arbitrary system headers.  */
25 #if defined _AIX && !defined __GNUC__
26  #pragma alloca
27 #endif
28 
29 #ifdef HAVE_CONFIG_H
30 # include <config.h>
31 #endif
32 
33 #include <stddef.h>
34 #include <stdlib.h>
35 #include "plural-exp.h"
36 
37 /* The main function generated by the parser is called __gettextparse,
38    but we want it to be called PLURAL_PARSE.  */
39 #ifndef _LIBC
40 # define __gettextparse PLURAL_PARSE
41 #endif
42 
43 #define YYLEX_PARAM	&((struct parse_args *) arg)->cp
44 #define YYPARSE_PARAM	arg
45 %}
46 %pure_parser
47 %expect 7
48 
49 %union {
50   unsigned long int num;
51   enum operator op;
52   struct expression *exp;
53 }
54 
55 %{
56 /* Prototypes for local functions.  */
57 static struct expression *new_exp PARAMS ((int nargs, enum operator op,
58 					   struct expression * const *args));
59 static inline struct expression *new_exp_0 PARAMS ((enum operator op));
60 static inline struct expression *new_exp_1 PARAMS ((enum operator op,
61 						   struct expression *right));
62 static struct expression *new_exp_2 PARAMS ((enum operator op,
63 					     struct expression *left,
64 					     struct expression *right));
65 static inline struct expression *new_exp_3 PARAMS ((enum operator op,
66 						   struct expression *bexp,
67 						   struct expression *tbranch,
68 						   struct expression *fbranch));
69 static int yylex PARAMS ((YYSTYPE *lval, const char **pexp));
70 static void yyerror PARAMS ((const char *str));
71 
72 /* Allocation of expressions.  */
73 
74 static struct expression *
new_exp(nargs,op,args)75 new_exp (nargs, op, args)
76      int nargs;
77      enum operator op;
78      struct expression * const *args;
79 {
80   int i;
81   struct expression *newp;
82 
83   /* If any of the argument could not be malloc'ed, just return NULL.  */
84   for (i = nargs - 1; i >= 0; i--)
85     if (args[i] == NULL)
86       goto fail;
87 
88   /* Allocate a new expression.  */
89   newp = (struct expression *) malloc (sizeof (*newp));
90   if (newp != NULL)
91     {
92       newp->nargs = nargs;
93       newp->operation = op;
94       for (i = nargs - 1; i >= 0; i--)
95 	newp->val.args[i] = args[i];
96       return newp;
97     }
98 
99  fail:
100   for (i = nargs - 1; i >= 0; i--)
101     FREE_EXPRESSION (args[i]);
102 
103   return NULL;
104 }
105 
106 static inline struct expression *
new_exp_0(op)107 new_exp_0 (op)
108      enum operator op;
109 {
110   return new_exp (0, op, NULL);
111 }
112 
113 static inline struct expression *
new_exp_1(op,right)114 new_exp_1 (op, right)
115      enum operator op;
116      struct expression *right;
117 {
118   struct expression *args[1];
119 
120   args[0] = right;
121   return new_exp (1, op, args);
122 }
123 
124 static struct expression *
new_exp_2(op,left,right)125 new_exp_2 (op, left, right)
126      enum operator op;
127      struct expression *left;
128      struct expression *right;
129 {
130   struct expression *args[2];
131 
132   args[0] = left;
133   args[1] = right;
134   return new_exp (2, op, args);
135 }
136 
137 static inline struct expression *
new_exp_3(op,bexp,tbranch,fbranch)138 new_exp_3 (op, bexp, tbranch, fbranch)
139      enum operator op;
140      struct expression *bexp;
141      struct expression *tbranch;
142      struct expression *fbranch;
143 {
144   struct expression *args[3];
145 
146   args[0] = bexp;
147   args[1] = tbranch;
148   args[2] = fbranch;
149   return new_exp (3, op, args);
150 }
151 
152 %}
153 
154 /* This declares that all operators have the same associativity and the
155    precedence order as in C.  See [Harbison, Steele: C, A Reference Manual].
156    There is no unary minus and no bitwise operators.
157    Operators with the same syntactic behaviour have been merged into a single
158    token, to save space in the array generated by bison.  */
159 %right '?'		/*   ?		*/
160 %left '|'		/*   ||		*/
161 %left '&'		/*   &&		*/
162 %left EQUOP2		/*   == !=	*/
163 %left CMPOP2		/*   < > <= >=	*/
164 %left ADDOP2		/*   + -	*/
165 %left MULOP2		/*   * / %	*/
166 %right '!'		/*   !		*/
167 
168 %token <op> EQUOP2 CMPOP2 ADDOP2 MULOP2
169 %token <num> NUMBER
170 %type <exp> exp
171 
172 %%
173 
174 start:	  exp
175 	  {
176 	    if ($1 == NULL)
177 	      YYABORT;
178 	    ((struct parse_args *) arg)->res = $1;
179 	  }
180 	;
181 
182 exp:	  exp '?' exp ':' exp
183 	  {
184 	    $$ = new_exp_3 (qmop, $1, $3, $5);
185 	  }
186 	| exp '|' exp
187 	  {
188 	    $$ = new_exp_2 (lor, $1, $3);
189 	  }
190 	| exp '&' exp
191 	  {
192 	    $$ = new_exp_2 (land, $1, $3);
193 	  }
194 	| exp EQUOP2 exp
195 	  {
196 	    $$ = new_exp_2 ($2, $1, $3);
197 	  }
198 	| exp CMPOP2 exp
199 	  {
200 	    $$ = new_exp_2 ($2, $1, $3);
201 	  }
202 	| exp ADDOP2 exp
203 	  {
204 	    $$ = new_exp_2 ($2, $1, $3);
205 	  }
206 	| exp MULOP2 exp
207 	  {
208 	    $$ = new_exp_2 ($2, $1, $3);
209 	  }
210 	| '!' exp
211 	  {
212 	    $$ = new_exp_1 (lnot, $2);
213 	  }
214 	| 'n'
215 	  {
216 	    $$ = new_exp_0 (var);
217 	  }
218 	| NUMBER
219 	  {
220 	    if (($$ = new_exp_0 (num)) != NULL)
221 	      $$->val.num = $1;
222 	  }
223 	| '(' exp ')'
224 	  {
225 	    $$ = $2;
226 	  }
227 	;
228 
229 %%
230 
231 void
232 internal_function
FREE_EXPRESSION(exp)233 FREE_EXPRESSION (exp)
234      struct expression *exp;
235 {
236   if (exp == NULL)
237     return;
238 
239   /* Handle the recursive case.  */
240   switch (exp->nargs)
241     {
242     case 3:
243       FREE_EXPRESSION (exp->val.args[2]);
244       /* FALLTHROUGH */
245     case 2:
246       FREE_EXPRESSION (exp->val.args[1]);
247       /* FALLTHROUGH */
248     case 1:
249       FREE_EXPRESSION (exp->val.args[0]);
250       /* FALLTHROUGH */
251     default:
252       break;
253     }
254 
255   free (exp);
256 }
257 
258 
259 static int
yylex(lval,pexp)260 yylex (lval, pexp)
261      YYSTYPE *lval;
262      const char **pexp;
263 {
264   const char *exp = *pexp;
265   int result;
266 
267   while (1)
268     {
269       if (exp[0] == '\0')
270 	{
271 	  *pexp = exp;
272 	  return YYEOF;
273 	}
274 
275       if (exp[0] != ' ' && exp[0] != '\t')
276 	break;
277 
278       ++exp;
279     }
280 
281   result = *exp++;
282   switch (result)
283     {
284     case '0': case '1': case '2': case '3': case '4':
285     case '5': case '6': case '7': case '8': case '9':
286       {
287 	unsigned long int n = result - '0';
288 	while (exp[0] >= '0' && exp[0] <= '9')
289 	  {
290 	    n *= 10;
291 	    n += exp[0] - '0';
292 	    ++exp;
293 	  }
294 	lval->num = n;
295 	result = NUMBER;
296       }
297       break;
298 
299     case '=':
300       if (exp[0] == '=')
301 	{
302 	  ++exp;
303 	  lval->op = equal;
304 	  result = EQUOP2;
305 	}
306       else
307 	result = YYERRCODE;
308       break;
309 
310     case '!':
311       if (exp[0] == '=')
312 	{
313 	  ++exp;
314 	  lval->op = not_equal;
315 	  result = EQUOP2;
316 	}
317       break;
318 
319     case '&':
320     case '|':
321       if (exp[0] == result)
322 	++exp;
323       else
324 	result = YYERRCODE;
325       break;
326 
327     case '<':
328       if (exp[0] == '=')
329 	{
330 	  ++exp;
331 	  lval->op = less_or_equal;
332 	}
333       else
334 	lval->op = less_than;
335       result = CMPOP2;
336       break;
337 
338     case '>':
339       if (exp[0] == '=')
340 	{
341 	  ++exp;
342 	  lval->op = greater_or_equal;
343 	}
344       else
345 	lval->op = greater_than;
346       result = CMPOP2;
347       break;
348 
349     case '*':
350       lval->op = mult;
351       result = MULOP2;
352       break;
353 
354     case '/':
355       lval->op = divide;
356       result = MULOP2;
357       break;
358 
359     case '%':
360       lval->op = module;
361       result = MULOP2;
362       break;
363 
364     case '+':
365       lval->op = plus;
366       result = ADDOP2;
367       break;
368 
369     case '-':
370       lval->op = minus;
371       result = ADDOP2;
372       break;
373 
374     case 'n':
375     case '?':
376     case ':':
377     case '(':
378     case ')':
379       /* Nothing, just return the character.  */
380       break;
381 
382     case ';':
383     case '\n':
384     case '\0':
385       /* Be safe and let the user call this function again.  */
386       --exp;
387       result = YYEOF;
388       break;
389 
390     default:
391       result = YYERRCODE;
392 #if YYDEBUG != 0
393       --exp;
394 #endif
395       break;
396     }
397 
398   *pexp = exp;
399 
400   return result;
401 }
402 
403 
404 static void
yyerror(str)405 yyerror (str)
406      const char *str;
407 {
408   /* Do nothing.  We don't print error messages here.  */
409 }
410